Question

Números Complexos!!!

Answer 1

$P(x)+i(x)P(x-i)=x^2+2\\ \\ \text{Ent\~ao}: \\ \\ P(i)+i(i)P(i-i)=i^2+2\\ \\ P(i)-P(0)=-1+2\\ \\ P(i)=P(0)+1\cdots\cdots \textcircled{1} \\ \\ \\ P(x)+i(x)P(x-i)=x^2+2\\ \\ P(0)+i(0)P(0-i)=2\\ \\ P(0)=2\\ \\ \text{De }\textcircled{1}: \boxed{P(i)=3}$