Question

Números complexos:
(1+i) (2-i)(3+2i)

Answer 1

 (1+i) (2-i)(3+2i)

(1+i) (2-i)= 2 -i + 2i - i^2 ==> 2 + i -(-1) => 2+1 + i ==>3 + i

(3 + i)(3+2i) = 9 + 6i + 3i + 2i^2  ==> 9 - 1 +9i

8 - 9i

Answer 2

(1+i)(2 - i) = 2 - i + 2i - i² = 3 + i

(3+i)(3 + 2i) = 9 + 6i + 3i + 2i² = 7 + 9i