Question

Número complexo. Resolver x2 +2x+5=0

Answer 1

x² + 2x + 5 = 0
a = 1, b = 2, c = 5

Δ = b² - 4ac
Δ = 2² - 4 . 1 . 5
Δ = 4 - 20
Δ = - 16

x = (- b ± √Δ)/2a
x = (- 2 ± √(- 16))/2 . 1
x = (- 2 ± 4i)/2

x' = (- 2 + 4i)/2 = - 1 + 2i
x'' = (- 2 - 4i)/2 = - 1 - 2i

x = - 1 + 2i
x = - 1 - 2i