Question

Numa pg tem se a1=3 e a8=384 calcule a razao

Answer 1

$> resolucao \\ \\ \geqslant progressao \: \: geometrica \\ \\ an = a1 \times q {}^{n - 1} \\ 384 = 3 \times q {}^{8 - 1} \\ \frac{384}{3} = q {}^{7} \\ 128 = q {}^{7} \\ 2 {}^{7} = q {}^{7} \\ q = 2 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant \leqslant \geqslant \geqslant$