Question

num triangulo isoceles,a base mede 8 cm e os angulos da base,30 °.quanto medem os dois lados que são congruentes?

Answer 1

Sen30˚  = ½ = h/x à x = 2h x² = 4² + h² (2h)²  =  16 + h² 4h² = 16 + h² (4 -1)h²  = 16 3 h²   = 16 h²    = 16/3 h = √(16/3) h = 4/√3 h = 4√3/√3√3 h = 4√3/3 ou h = 4. √3    cm       è                                                                                                                                              3   x² = 4² + h² x² = 16 + h² x² = 16 + (4. √3) ²                 3 x = √(16 + 16 . 3)                     9 x = √(16 + 16/3) x = √(48/3 + 16/3) x = √(64/3) x = √64 / √3 x = 8/√3 x = (8√3)/ (√3√3) x = 8√3  cm  (resposta)         3    
Resolvido no word e colado aqui.