Question

num recipiente estão contidas 1,204.10 elevado a 22 moléculas de água qual a massa de água desse recipiente?

Answer 1

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•  Encontrando a quantidade de mols de água presente no recipiente (quantidade de matéria):

$\begin{array}{ccc} \mathsf{1~mol}&\leftrightarrow&\mathsf{6,\!02\cdot 10^{23}}\textsf{ mol\'eculas}\\\\ \mathsf{n}&\leftrightarrow&\mathsf{1,\!204\cdot 10^{22}}\textsf{ mol\'eculas} \end{array}\\\\\\\\ \mathsf{\dfrac{1}{n}=\dfrac{6,\!02\cdot 10^{23}}{1,\!204\cdot 10^{22}}}$

$\mathsf{n=\dfrac{1,\!204\cdot 10^{22}}{6,\!02\cdot 10^{23}}}\\\\\\ \mathsf{n=\dfrac{1,\!204}{6,\!02}\cdot 10^{22-23}}\\\\\\ \mathsf{n=0,\!2\cdot 10^{-1}}\\\\\\ \mathsf{n=0,\!02~mol}\qquad\quad\checkmark$


•   Massa molar da água:

$\mathsf{M=2\cdot 1+16}\\\\ \mathsf{M=18~g/mol}$


Montando a proporção:

$\begin{array}{ccc} \mathsf{1~mol}&\leftrightarrow&\mathsf{18~g}\\\\ \mathsf{0,\!02~mol}&\leftrightarrow&\mathsf{m} \end{array}\\\\\\\\ \mathsf{\dfrac{1}{0,\!02}=\dfrac{18}{m}}\\\\\\ \mathsf{m=0,\!02\cdot 18}\\\\\\ \boxed{\begin{array}{c}\mathsf{m=0,\!36~g} \end{array}}\quad\longleftarrow\quad\textsf{esta \'e a resposta.}$


Bons estudos! :-)