Question

Num recipiente contendo 279 g de aguá, a 10°c, coloca- se um pedaço de chumbo de 500 g, a 200°c. Adimitindo- se que só haja troca de calor entrega água e o chumbo, a temperatura de equilíbrio térmico em °c, será de ( dados: calor especifico da água = 1cal/g°c; calor especifico do chumbo = 0,03 cal/g°c; temperatura de fusão do chumbo = 327°c): a) 15 b) 20 C) 27 d) 50 e) 73

Answer 1

$Ola'~~~~\mathbf{Meiry} \\ \\ ~~~~~~~~~\acute{a}gua~~~~~~~~~~~~~~~~~~~~~~~~~~~~chumbo\\ \begin{tabular}{|c|c|c}m=279g \\ T=10\°C \\ C_e=1cal/g\°C \\ \cline{1-1}\end{tabular}~~~~~~~~~~~~\begin{tabular}{|c|c|c}m=500g \\ T=100\°C \\ C_e=0,03cal/g \°C \\ \cline{1-1}\end{cases} \\ ~~~~~~~~~~~~\underline{\bigg|~~~~~~~~~~~~T_e=?~~~~~~~~~~~~~~~~~\bigg|} \\ \\ Se~sabe~que: \\ \\ Q_{ab}+Q_{ced}=0~~~---\ \textgreater \ por~tanto~temos: \\ \\ 279.1.(T_e-10)+500.(0,03).(T_e-200)=0~~--\ \textgreater \ desenvolvendo~$

$279T_e-2790+15T_e-3000=0 \\ \\ 279T_e+15T_e=3000+2790 \\ \\ 294T_e=5790 \\ \\ T_e=19,693877.....~~~~--\ \textgreater \ aredondando~seria \\ \\ \boxed{\boxed{T_e=20}}~~---\ \textgreater \ \textcircled{b} \\ \\ \mathbb{iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii}\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~Espero~ter~ajudado!!$