Question

nos triângulos retangulos seguintes calcule x:

Answer 1

Olá

a)

cos α = (c. adjacente)/(hipotenusa)
cos 30° = 16/x
(√3)/2 = 16/x
x√3 = 32
x = 32/√3
$x = \frac{32 \sqrt{3} }{3}$

b)
sen y = (c. oposto)/(hipotenusa)
sen y = 13/26
$sen \: y = \frac{1}{2}$
y = 30°

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Abraços!!

Answer 2

cosX=A/H
cos30°=16/x
√3/2=16/x
√3.x=2.16
√3x=32
x=32/√3
x=32√3/3