Question

nos triângulos retângulos a seguir, determine a medida desconhecida X

​

Answer 1

Resposta:

$x = 2 \sqrt{2}$

Explicação passo-a-passo:

Usando o Teorema de Pitágoras, temos:

${a}^{2} = {b}^{2} + {c}^{2} \\ {(6 \sqrt{2} )}^{2} = {8}^{2} + {c}^{2} \\ 36 \times 2 = 64 + {c}^{2} \\ 72 - 64 = {c}^{2} \\ c = \sqrt{8} = 2 \sqrt{2}$

Espero ter ajudado!

Answer 2

Caso tenha problemas para visualizar a resposta experimente abrir pelo navegador https://brainly.com.br/tarefa/32740500?answering=true&answeringSource=feedPublic%2FhomePage%2F1

$\Large\boxed{\sf{\underline{Teorema~de~Pit\acute{a}goras}}}\\\boxed{\begin{array}{c}\sf{Em~todo~tri\hat{a}ngulo~ret\hat{a}ngulo}\\\sf{A~soma~dos~quadrados~dos~catetos}\\\sf{\acute{e}~igual~ao~quadrado~da~hipotenusa}\end{array}}\\\huge\boxed{\boxed{\boxed{\boxed{\boxed{\tt{b^2+c^2=a^2}}}}}}$

$\bf{Dados:}\\\sf{b=x}\\\sf{c=8}\\\sf{a=6\sqrt{2}}\\\Large\rm{\underline{Soluc_{\!\!,}\tilde{a}o:}}\\\sf{x^2+8^2=(6\sqrt{2})^2}\\\sf{x^2+64=36\cdot2}\\\sf{x^2+64=72}\\\sf{x^2=72-64}\\\sf{x^2=8}\\\sf{x=\sqrt{8}}\\\begin{array}{c|l}\sf{8&2}\\\sf{4&2}\\\sf{2&2}\\\sf{1}}\end{array}\\\sf{8=2^2\cdot2}\\\sf{x=\diagup\!\!\!\!\sqrt{2^{\diagup\!\!\!2}\cdot2}}\\\huge\boxed{\boxed{\boxed{\boxed{\tt{x=2\sqrt{2}}}}}}$