Question

No triângulo ABC calcule as medidas X e Y em centímetros.

Answer 1

Explicação passo-a-passo:

• $\sf sen~30^{\circ}=\dfrac{cateto~oposto}{hipotenusa}$

$\sf \dfrac{1}{2}=\dfrac{x}{100}$

$\sf 2x=100\cdot1$

$\sf 2x=100$

$\sf x=\dfrac{100}{2}$

$\sf \red{x=50~cm}$

• $\sf cos~30^{\circ}=\dfrac{cateto~adjacente}{hipotenusa}$

$\sf \dfrac{\sqrt{3}}{2}=\dfrac{y}{100}$

$\sf 2y=100\sqrt{3}$

$\sf y=\dfrac{100\sqrt{3}}{2}$

$\sf \red{y=50\sqrt{3}~cm}$

Answer 2

Resposta:

x = 50

y = 5√2

Explicação passo-a-passo:

sen x = cat oposto

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hipotenusa

sen 30 = 1/2

sen 30 = x/100

1/2 = ×/100

100 . 1/2 = x

100 / 2 = x

50 = x

cos 30 = √3/2

√3/2 = y/100

100√3 / 2 = y

50√3 = y

50√3 . √3/√3

50.3 / √3

150 / √3 (150 = √2. 3. 5²) = 5√2. √3

5. √2 . √3 / √3

5√2 = y