Question

no triangulo AB=20 cm e AD=2DC, Descubra a medida de AE e EB

Answer 1

Seja x o lado do losango:

AM/MP = AB/BC ----> (20 - x)/x = 20/5 ----> x = 4

Área do losango ---> A = D*d/2 ----> A = [2*x*sen(T/2)]*[2*xcos(T/2)]/2

A = x²*[2*sen(T/2)*cos(T/2)] ----> A = x²*senT ----> 8 = 4²*senT ----> senT = 1/2 ---> T = 30º

:)