Question

no triângulo a seguir, ultilize o teorema de Pitágoras para calcular o calor de x
urgente...​

Answer 1

C) (hip)*2= (cat)*2+(cat)*2

(x)*2=(6)*2+(8)*2

x*2= 36+64

x*2= 100

x=✓100

x= 10

D) (hip)*2= (cat)*2+(cat)*2

(15)*2= (x)*2+(12)*2

225= x*2+ 144

x*2+144=225

x*2=225-144

x*2= 81

x=✓81

X=9

E) (hip)*2= (cat)*2+(cat)*2

(25)*2=(x)*2+(24)

625= x*2+ 576

x*2+576= 625

x*2= 625-576

x*2= 49

x=✓49

X= 7

F) (hip)*2= (cat)*2+(cat)*2

(x)*2= (3)*2+(4)*2

x*2= 9+16

x*2= 25

x=✓25

X=5

Answer 2

olá!

C) (hip)*2= (cat)*2+(cat)*2

(x)*2=(6)*2+(8)*2

x*2= 36+64

x*2= 100

x=✓100

x= 10

D) (hip)*2= (cat)*2+(cat)*2

(15)*2= (x)*2+(12)*2

225= x*2+ 144

x*2+144=225

x*2=225-144

x*2= 81

x=✓81

X=9

E) (hip)*2= (cat)*2+(cat)*2

(25)*2=(x)*2+(24)

625= x*2+ 576

x*2+576= 625

x*2= 625-576

x*2= 49

x=✓49

X= 7

F) (hip)*2= (cat)*2+(cat)*2

(x)*2= (3)*2+(4)*2

x*2= 9+16

x*2= 25

x=✓25

X=5

espero ter ajudado.