no desenvolvimento do binomio (x-3)^5 o coeficiente do quarto termo é?
a) - 15
b) 90
c) - 243
d) - 247
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cn,p= n!/n!(n-p)!
C5,0= 5!/5!(5-0)! =5!/5!= 1
C5,1 = 5!1!(5-1)!= 5!/1!4!= 5x4!/1!4!= 5/1= 5
C5,2= 5!/2!(5-2)! = 5!/2!3!= 5x4x3!/2x3=
20/2 = 10
C5,3= 5!/3!(5-3)! = 5!3!2! =5x4x3x2!/3x2x2!=
5x4x3x2!/3x2x2! = 120/6= 20
C5,4= 5!/4!(5-4)!= 5!/4!1!= 5x4!/1!x4!= 5/1=5
C5,5= 5!/5!(5-5)!= 5!/5!0!= 5!/5!=1
C5,0= 5!/5!(5-0)! =5!/5!= 1
C5,1 = 5!1!(5-1)!= 5!/1!4!= 5x4!/1!4!= 5/1= 5
C5,2= 5!/2!(5-2)! = 5!/2!3!= 5x4x3!/2x3=
20/2 = 10
C5,3= 5!/3!(5-3)! = 5!3!2! =5x4x3x2!/3x2x2!=
5x4x3x2!/3x2x2! = 120/6= 20
C5,4= 5!/4!(5-4)!= 5!/4!1!= 5x4!/1!x4!= 5/1=5
C5,5= 5!/5!(5-5)!= 5!/5!0!= 5!/5!=1
ronnax120pajf9b:
desculpa aperter antes, a resposta é (-3)^5= -243
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