Question

no calculo íntegral qual a resposta para a integral indefinida de √× dx

Answer 1

$\int { \sqrt{x} } \, dx = \int x^{ \frac{1}{2} }\, dx = \dfrac{x^{ \frac{1}{2}+1 }}{ \frac{1}{2}+1 } = \frac{2x^{\frac{3}{2}}}{3}\\\\ \int { \sqrt{x} } \, dx = \frac{2x^{\frac{3}{2}}}{3} + k,\;\;com\;k\;constante\\\\ ou \\\\ \int { \sqrt{x} } \, dx = \frac{2 \sqrt{x^3} }{3} + k,\;\;com\;k\;constante$

Answer 2

$\mathsf{\int(\sqrt{x})dx=\int({x}^{\frac{1}{2}})dx}$

$\large\boxed{\boxed{\mathsf{\int(\sqrt{x})dx=\dfrac{2}{3}{x}^{\frac{3}{2}}+K}}}$