Question

necessito de ajuda ksks:

|x| = x^2

Answer 1

$|x| = {x}^{2} \\ |x| - {x}^{2} = 0 \begin{gathered}\begin{cases} {x - {x}^{2} = 0 \: , x\geq0}\\{ - x - {x}^{2} = 0 \: ,x < 0} \end{cases}\end{gathered}$

$x - {x}^{2} = 0 \\ x \times (1 - x) = 0 \begin{gathered}\begin{cases} {x = 0}\\{1 - x = 0} \end{cases}\end{gathered} \\ x = 0 \\ x = 1$

$- x - {x}^{2} = 0 \\ - x \times (1 + x) = 0 \\ x \times (1 + x) = 0 \begin{gathered}\begin{cases} {x = 0}\\{1 + x = 0} \end{cases}\end{gathered} \\ x = 0 \\ x = - 1$

${x - {x}^{2} = 0 \: , x\geq0}\begin{gathered}\begin{cases} {x = 0}\\ \: \: \: \: \: \: \: \: \: \: ,x \geq0\\ {x = 1} \end{cases}\end{gathered}\\{ - x - {x}^{2} = 0 \: ,x < 0} \begin{gathered}\begin{cases} {x = 0}\\ \: \: \: \: \: \: \: \: \: \: \: ,x < 0\\ {x = - 1} \end{cases}\end{gathered}$

A equação tem 3 soluções

$x_{1} = - 1 \\ x_{2} = 0 \\ x_{3} = 1$

$\mathcal{Bons \: estudos } \\ \displaystyle\int_ \empty ^ \mathbb{C}     \frac{ - b \: ± \:  \sqrt{ {b}^{2} - 4 \times a \times c } }{2 \times a} d{ t } \boxed{ \boxed{ \mathbb{\displaystyle\Re}\sf{ \gamma  \alpha }\tt{ \pi}\bf{ \nabla}}}$