Question

nas figuras as retas R,S e t são paralelas.calcule a medida do segmento AB.
B)AC = 13,5cm; EF = 4cm e DE = 5cm.

Answer 1

$\frac{AC}{AB} = \frac{DF}{EF} \\ \\ \frac{13,5}{AB} = \frac{5+4}{4} \\ \\ \frac{13,5}{AB} = \frac{9}{4} \\ \\ 9AB=4.(13,5) \\ \\ 9AB=54 \\ \\ AB=54\div9 \\ \\ AB=6cm$