Matemática, perguntado por joaomarcelomartins15, 2 meses atrás

Não estou conseguindo fazer alguem me ajuda

Anexos:

Soluções para a tarefa

Respondido por augustolupan
2

Resposta:

\boxed{\dfrac{3\sqrt{5x}}{x.y^2}}

Explicação passo a passo:

\dfrac{\sqrt{90x^4y}}{\sqrt{2x^5y^5}} = \\\\\\\dfrac{\sqrt{2.3^2.5x^4y}}{\sqrt{2(x^4.x)(y^4.y)}} = \\\\\\\dfrac{3x^2\sqrt{2.5y}}{x^2y^2\sqrt{2xy}} = \\\\\\\dfrac{3\sqrt{2.5y}}{y^2\sqrt{2xy}} = \\\\\\\dfrac{3\sqrt{2.5y}}{y^2\sqrt{2xy}}.\dfrac{\sqrt{2xy}}{\sqrt{2xy}} = \\\\\\\dfrac{3\sqrt{2.5y.2xy}}{y^2.2xy} = \\\\\\\dfrac{3\sqrt{5.2^2xy^2}}{y^2.2xy} = \\\\\\\dfrac{3.2.y\sqrt{5x}}{y^2.2xy} = \\\\\\\dfrac{3\sqrt{5x}}{y^2x} = \\\\\\\boxed{\dfrac{3\sqrt{5x}}{x.y^2}}

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