Question

Na função Y= x2 -4x+3, suas raizes sao quais?

Answer 1

Oi!
$y = x^2 - 4x + 3 \\ \\ \Delta = b^2 - 4ac \\ \Delta = (- 4)^2 - 4 \times 1 \times 3 \\ \Delta = 16 - 12 \\ \Delta = 4$

$x = \frac{-b \pm \sqrt{\Delta}}{2a} \\ x= \frac{-(-4)\pm \sqrt{4}}{2 \times 1} \\ x= \frac{4 \pm 2}{2}$

$x' = \frac{4 + 2}{2} = \frac{6}{2} = 3$
$x" \frac{4 - 2}{2} = \frac{2}{2} = 1$

S = { 1, 3}

Bons estudos.