Question

Na função h(x) = 4x + 2t, ℎ(2) = −8, h(4) = 0, então o valor de t é:

Answer 1

$\Large\boxed{\begin{array}{l}\sf h(x)=4x+2t\\\sf h(2)=4\cdot2+2t\\\sf -8=8+2t\\\sf 2t+8=-8\\\sf 2t=-8-8\\\sf 2t=-16\\\sf t=-\dfrac{16}{2}\\\\\sf t=-2\end{array}}$