Question

na figura temos que alfa = 30° e beta = 60° e h = 6V2cm. sabendo que V6 = 2,44 determine a medida do lado AC do triangulo

Answer 1

tg 30 = x/6\/2 
tg 30 = x\/2/6.2
tg 30 = x\/2/12
x\/2/12 = \/3/3
3x\/2 = 12\/3
3x = 12\/3/ \/2
3x = 12\/3\/2 / 2
3x = 12\/6 / 2
3x = 6\/6
x = 6\/6/3
x = 2\/6
x = 2 . 2,44
x = 4,88

tg 60 = y/6\/2
\/3 = y\/2/6.2
\/3 = y\/2/12
y\/2 = 12\/3
y = 12\/3 / \/2
y = 12\/3.\/2 / 2
y = 6\/6
y = 6 . 2,44
y = 14,64

AC = x + y
AC = 4,88 + 14,64
AC = 19,52 cm