Matemática, perguntado por mirellacristina1901, 10 meses atrás

Na figura, temos a//b//c. Sabendo-se que AB=14, AC= 42, DE=18. Qual a medida de DF? *
a)32
b)54
c)56
d)60

Anexos:

mirellacristina1901: td bem?
mirellacristina1901: Q bom
mirellacristina1901: Td também :)
mirellacristina1901: :)
giovannadasilvacarmo: oii
mirellacristina1901: oie
giovannadasilvacarmo: nossa

Soluções para a tarefa

Respondido por decioignacio
5

Resposta:

Explicação passo-a-passo:

_AB_ = _DE_

 BC        EF

_14_ = _18_

 28       EF

EF = _28×18_

           14

EF = 2×18

EF = 36

DF = DE + EF

DF = 18 + 36

DF = 54


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Respondido por giovannadasilvacarmo
2

Resposta:

_AB_ = _DE_

BC        EF

_14_ = _18_

28       EF

EF = _28×18_

          14

EF = 2×18

EF = 36

DF = DE + EF

DF = 18 + 36

DF = 54

Explicação passo-a-passo:

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