Question

na figura determine as medidas X e Y sabendo que r//s//t e a medida do segmento AC=27

Answer 1

$\frac{a+b}{c+d} = \frac{a}{c} \frac{x}{y} = \frac{5}{4}$

x+y =27

$\frac{x+y}{5+4} = \frac{x}{5}$$\frac{27}{5+4} = \frac{x}{5}$

9x=27*5
9x=135
x=$x= \frac{135}{9} = 15$
x+y=27
15+y=27
y=27-15
y=12