Question

na figura abaixo, o valor de x é:​

Answer 1

$\boxed{\begin{array}{l}\sf Perceba~que~o~cateto~menor~do~tri\hat angulo~ret\hat angulo\\\sf \acute e~dado~por~23-15=8.\\\sf agora~podemos~aplicar\\\sf o~teorema~de~Pit\acute agoras~no~tri\hat angulo\\\sf onde~a~hipotenusa~\acute e~10,e~os~catetos~s\tilde ao~8~e~x.\\\sf assim~temos:\\\sf x^2+8^2=10^2\\\sf x^2+64=100\\\sf x^2=100-64\\\sf x^2=36\\\sf x=\sqrt{36}\\\sf x=6\\\sf corrija~o~gabarito.\end{array}}$