Question

Na figura abaixo, AE // BD. Nessas condições determine os valores de a e b

Answer 1

$\Large\boxed{\begin{array}{l}\sf\dfrac{3x+x}{3x}=\dfrac{a+b}{b}\\\\\sf\dfrac{4\backslash\!\!\!x}{3\backslash\!\!\!x}=\dfrac{8}{b}\\\\\sf 4b=24\\\sf b=\dfrac{24}{4}\\\\\sf b=6\\\sf a+b=8\\\sf a+6=8\\\sf a=8-6\\\sf a=2\end{array}}$