na figura a//b//c//,calcule o valor de x?
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Solução!
![\dfrac{3x+1}{5x-2}= \dfrac{10}{15}\\\\\\
\dfrac{3x+1}{5x-2}= \dfrac{2}{3}\\\\\\
3(3x+1)=2(5x-2)\\\\\\
9x+3=10x-4\\\\\\
9x-10x=-4-3\\\\\\
-x=-7\\\\\
x= \dfrac{-7}{-1} \\\\\\\
\boxed{x=7}](https://tex.z-dn.net/?f=+%5Cdfrac%7B3x%2B1%7D%7B5x-2%7D%3D+%5Cdfrac%7B10%7D%7B15%7D%5C%5C%5C%5C%5C%5C%0A%0A+++%5Cdfrac%7B3x%2B1%7D%7B5x-2%7D%3D+%5Cdfrac%7B2%7D%7B3%7D%5C%5C%5C%5C%5C%5C%0A3%283x%2B1%29%3D2%285x-2%29%5C%5C%5C%5C%5C%5C%0A9x%2B3%3D10x-4%5C%5C%5C%5C%5C%5C%0A9x-10x%3D-4-3%5C%5C%5C%5C%5C%5C%0A-x%3D-7%5C%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B-7%7D%7B-1%7D+%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7Bx%3D7%7D "\dfrac{3x+1}{5x-2}= \dfrac{10}{15}\\\\\\
\dfrac{3x+1}{5x-2}= \dfrac{2}{3}\\\\\\
3(3x+1)=2(5x-2)\\\\\\
9x+3=10x-4\\\\\\
9x-10x=-4-3\\\\\\
-x=-7\\\\\
x= \dfrac{-7}{-1} \\\\\\\
\boxed{x=7}")
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Solução!
Boa noite!
Bons estudos!
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