Question

multiplique (3+5i).(2-7i)

Answer 1

Olá,

i² = -1, então, aplicando a distributiva..

$(3+5i)\cdot(2-7i)\\ 6-21i+10i-35i^2\\ 6-11i-35\cdot(-1)\\ 6-11i+35\\ 41-11i$