Question

Multiplicar numeros complexos (3+4i).(2-6i)

Answer 1

Fica assim:

$(3 + 4i). (2 - 6i) \\ \\ \\ 3.2 - 3,6i + 4i.2 - 4i.6i \\ \\ \\ 6 - 18i + 8i + 24 \\ \\ \\ =\ \textgreater \ 30 - 10i$