Question

MUITO URGENTE! Lei Senos e Cossenos


Determine a medida x indicada no triângulo abaixo:

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{\dfrac{x}{sen\:60\textdegree} = \dfrac{8}{sen\:45\textdegree}}$

$\mathsf{\dfrac{x}{\dfrac{\sqrt{3}}{2}} = \dfrac{8}{\dfrac{\sqrt{2}}{2}}}$

$\mathsf{\dfrac{2x}{\sqrt{3}} = \dfrac{16}{\sqrt{2}}}$

$\mathsf{2x\sqrt{2}} = 16\sqrt{3}}$

$\mathsf{x\sqrt{2}} = 8\sqrt{3}}$

$\mathsf{x = \dfrac{8\sqrt{3}}{\sqrt{2}}}$

$\mathsf{x = \dfrac{8\sqrt{6}}{2}}$

$\boxed{\boxed{\mathsf{x = 4\sqrt{6}\:cm}}}\leftarrow\textsf{letra C}$