Question

MRUV : qual o tempo que um objeto em queda livre cai 3000 metros

Answer 1

Resposta:

t≅24,5s

Explicação:

$h=\frac{g*t^2}{2} \\3000=\frac{10t^2}{2}\\6000=10t^2\\600=t^2\\t = \sqrt{600} \\t=24,5s$

Answer 2

$Dados:\left \{ {{h=3000} \atop {g=10}} \right. \\\\Resposta:\\\\h=\frac{gt^{2} }{2} \\\\3000=\frac{10.t^{2} }{2} \\\\6000=10.t^{2}\\\\\frac{6000}{10} =t^{2}\\\\t^{2}=600\\\\t=\sqrt{600} \\\\t=24,49$