Question

Monte uma matriz A(4x4) que satisfaça a lei Aij= 3i +2j - 5

Answer 1

$\boxed{\begin{array}{l}\sf a_{11}=3\cdot1+2\cdot1-5=3+2-5=0\\\sf a_{12}=3\cdot1+2\cdot2-5=3+4-5=2\\\sf a_{13}=3\cdot1+2\cdot3-5=3+6-5=4\\\sf a_{14}=3\cdot1+2\cdot4-5=3+8-5=6\\\sf a_{21}=3\cdot2+2\cdot1-5=6+2-5=3\\\sf a_{22}=3\cdot2+2\cdot2-5=6+4-5=5\\\sf a_{23}=3\cdot2+2\cdot3-5=6+6-5=7\\\sf a_{24}=3\cdot2+2\cdot4-5=6+8-5=9\end{array}}$

$\boxed{\begin{array}{l}\sf a_{31}=3\cdot3+2\cdot1-5=9+2-5=6\\\sf a_{32}=3\cdot3+2\cdot2-5=9+4-5=8\\\sf a_{33}=3\cdot3+2\cdot3-5=9+6-5=10\\\sf a_{34}=3\cdot3+2\cdot4-5=9+8-5=12\\\sf a_{41}=3\cdot4+2\cdot1-5=12+2-5=9\\\sf a_{42}=3\cdot4+2\cdot2-5=12+4-5=11\\\sf a_{43}=3\cdot4+2\cdot3-5=12+6-5=13\\\sf a_{44}=3\cdot4+2\cdot4-5=12+8-5=15\end{array}}$

$\large\boxed{\begin{array}{l}\sf A=\begin{bmatrix}\sf0&\sf2&\sf4&\sf6\\\sf3&\sf5&\sf7&\sf9\\\sf6&\sf8&\sf10&\sf12\\\sf9&\sf11&\sf13&\sf15\end{bmatrix}\end{array}}$