Question

Modulo 1 e ja to surtanto

Answer 1

Explicação passo-a-passo:

Como DE//BC, podemos utilizar o Teorema de Tales:

$\dfrac{x}{x+3} =\dfrac{10}{15} \\\\\dfrac{x}{x+3} =\dfrac{2}{3} \\\\3x=2.(x+3)\\\\3x=2x+6\\\\3x-2x=6\\\\\boxed{x=6}$

Calculando o lado AB:

$AB=x+x+3\\\\AB=6+6+3\\\\\boxed{\boxed{AB=15}}$