Matemática, perguntado por roseanyoliveira14099, 5 meses atrás

mmc(15,25)
Mmc(16,26)
Mmc(54,90)
Mmc(18,21)
Mmc(42,56)
Mmc(48,60

Soluções para a tarefa

Respondido por jvsetubal
1

Resposta:

15, 25 | 3

5, 25 | 5

1, 5 | 5

1, 1 | 1 = 75

16, 26 | 2

8, 13 | 2

4, 13 | 2

2, 13 | 2

1, 13 | 13

1, 1 | 1 = 208

54, 90 | 2

27, 45 | 3

9, 15 | 3

3, 5 | 3

1, 5 | 5

1, 1 | 1 = 270

18, 21 | 2

9, 21 | 3

3, 7 | 3

1, 7 | 7

1, 1 | 1 = 126

42, 56 | 2

21, 28 | 2

21, 14 | 2

21, 7 | 3

7, 7 | 7

1, 1 | 1 = 168

48, 60 | 2

24, 30 | 2

12, 15 | 2

6, 15 | 2

3, 15 | 3

1, 5 | 5

1, 1 | 1 = 240

Explicação passo a passo:

Respondido por Usuário anônimo
1

MMC(15,25)

15, 25 | 3

5, 25 | 5

1, 5 | 5

1, 1 | 1

mmc = 3 \times  {5}^{2}  = 75

MMC(16,26)

16, 26 | 2

8, 13 | 2

4, 13 | 2

2, 13 | 2

1, 13 | 13

1, 1 | 1

mmc =  {2}^{4}  \times 13 = 208

MMC(54,90)

54, 90 | 2

27, 45 | 3

9, 15 | 3

3, 5 | 3

1, 5 | 5

1, 1 | 1

mmc = 2 \times  {3}^{3}  \times  5 = 270

MMC(18,21)

18, 21 | 2

9, 21 | 3

3, 7 | 3

1, 7 | 7

1, 1 | 1

mmc = 2 \times  {3}^{2}  \times 7 = 126

MMC(42,56)

42, 56 | 2

21, 28 | 2

21, 14 | 2

21, 7 | 3

7, 7 | 7

1, 1 | 1

mmc =  {2}^{3}  \times 3 \times 7 = 168

MMC(48,60)

48, 60 | 2

24, 30 | 2

12, 15 | 2

6, 15 | 2

3, 15 | 3

1, 5 | 5

1, 1 | 1

mmc =  {2}^{4}  \times 3 \times 5 = 240

\Large\mathscr{\red{Attard}}

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