Matemática, perguntado por borgesfelipe766, 7 meses atrás

minimo multiplo comum do 8 e 12 e 45

Soluções para a tarefa

Respondido por luissnunes2008
0

Resposta:

360

m.m.c(8,12,45)=360

M8{8,16,24,32,40,48,56,64,72,80,88,96,104,112,120,128,136,144,152,160,168,176,184,192,200,208,216,224,232,240,248,256,264,272,280,288,296,304,312,320,328,336,344,352,360}

M12{12,24,36,48,60,72,84,96,108,120,132,144,156,168,180,192,204,216,228,240,252,264,276,288,300,312,324,336,348,360}

M45{45,90,135,180,225,270,315,360}

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