Question

mim ajudem urgente?

Answer 1

$n(A\cup B)=24\\ n(A\cap B)=4\\ n(B\cup C)=16\\ n(A- C)=11\\ n(B- C)=10\\ \\ \\ n(A\cup B)=n(A)+n(B)-n(A\cap B)=24\\ n(A)+n(B)-4=24\\ \boxed{n(A)+n(B)=28}\\ \\ \\ n(B\cup C)=\boxed{n(B)=16}\\ \boxed{\n(A)=12}$

$n(A-B) = n(A) - n(A\cap B)\\ \\ n(A-B) = 12 - 4 \\ \\ \boxed{n(A-B) =8}$

$n(A\cap B \cap C) = n(A\cap C )\\ \\ n(A\cap C )=n(A)-n(A-C)\\ \\ n(A\cap C )=12-11\\ \\ \\ \boxed{n(A\cap C )=1}$