Question

MIM AJUDEM PFVR!!!!
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Answer 1

Resposta:

a)

$3x - 30^{o} + x + 10^{o} = 180^{o}\\4x - 20^{o} = 180^{o}\\4x = 180^{o} - 20^{o} = 160^{o}\\x = \frac{160}{4} = 40^{o}$

b)

$5x - 10^{o} + 40^{o} = 180^{o}\\5x + 30^{o} = 180^{o}\\5x = 180^{o} - 30^{o} = 150^{o}\\x = \frac{150}{5} = 30^{o}$

c)

$90^{o} + x + 2x = 180^{o}\\3x = 180^{o} - 90^{o} = 90^{o}\\x = \frac{90}{3} = 30^{o}$