Question

mim ajuda pfvr
pfvr ​

Answer 1

Resposta:

Explicação passo-a-passo:

a) $(3x^{2}-4x-7)+(4x^{2}+4x+3)=\\3x^{2}+4x^{2}-4x+4x-7+3=\\(3+4)x^{2}+(4-4)x+(-7+3)=\\7x^{2}-4$

b) $(2x^{5}-2x^{3}+4x)+(5x^{5}+4x^{3}-6x)=\\2x^{5}+5x^{5}-2x^{3}+4x^{3}+4x-6x=\\(2+5)x^{5}+(4-2)x^{3}+(4-6)x=\\7x^{5}+2x^{3}-2x$

c)$(-2x^{2}+4x+7)-(3x^{2}+5x+8)=\\-2x^{2}+4x+7-3x^{2}-5x-8=\\(-2-3)x^{2}+(4-5)x+(7-8)=\\-5x^{2}-x-1$