Question

miim ajuuuda ,(x+1)=
(x+7)(x+3)=
(x-8)=
(3x+4)=
(2x-3)(2x+3)

Answer 1

a)
x + 1 = 0
x = - 1

b)
(x+7)(x + 3) = x² + 3x + 7x + 21
x² + 10x + 21 = 0
a=1; b = 10, c = 21

Δ = 100 - 4.1.21
Δ = 100 - 84
Δ = 16

x' = - 10 + 4 = 6/2 = 3
          2

x" = - 10 - 4 = - 14/2 = - 7
          2

x = 3 e x = - 7
c)
x - 8 = 0
x = 8

d)
3x + 4 = 0
3x = - 4
x = - 4/3

e)
(2x - 3) (2x + 3)
4x² + 6x - 6x - 9 = 4x² - 9

4x² = 9
x² = 9/4
x = √9
      √4

x = +/- 3/2