Question

mi ajudar por favooooo​

Answer 1

Resposta:

a) $2^2$

b) $x^{-2}$

c) $2^{3x+3}$

d) $5^4$

Explicação passo-a-passo:

Propriedades:

1) $a^x\times a^y = a^{x+y}$

2) $a^x\div a^y = a^{x-y}$

3) $(a^x)^y=a^{x\times y}$

4) $a^{-x}=\frac{1}{a^x}$

a)

$(2^4\times2^6)\div(2^5\times2^3)$

$=(2^{4+6})\div(2^{5+3})$

$=2^{10}\div2^8$

$=2^{10-8}$

$=2^2$

b)

$(x^4\times x^2\times x^3)^2\div(x^4)^5$

$=(x^{4+2+3})^2\div(x^4)^5$

$=(x^9)^2\div(x^4)^5$

$=(x^{9\times2})\div(x^{4\times5})$

$=x^{18}\div x^{20}$

$=x^{18-20}$

$=x^{-2}$

$=\frac{1}{x^2}$

c)

$(2^{5x-1}\times2^{x+2})\div(2^{3x-2})$

$=(2^{5x-1+(x+2)})\div(2^{3x-2})$

$=(2^{5x-1+x+2})\div(2^{3x-2})$

$=(2^{6x+1})\div(2^{3x-2})$

$=2^{6x+1-(3x-2)$

$=2^{6x+1-3x+2$

$=2^{3x+3}$

d)

$(5^2\times5^3)\div(5^1\times5^0)$

$=(5^{2+3})\div(5^{1+0})$

$=5^5\div5^1$

$=5^{5-1}$

$=5^4$