Question

Metade de ( y + 610 ) e igual a 10 ( y- 20 ) neste caso o y tera um valor exato? Quanto?

Answer 1

$\large\boxed{\begin{array}{l}\sf\dfrac{y+610}{2}=10(y-20)\\\\\sf 20(y-20)=y+610\\\sf 20y-400=y+610\\\sf 20y-y=610+400\\\sf 19y=1010\\\sf y=\dfrac{1010}{19}\\\\\sf \end{array}}$