Question

menos a letra d que eu já fiz​

Answer 1

Olá, siga a explicação:

A)

$\sqrt{0,4444...} + 0,3333333 - 0,4 \\ \\ 0,6666.. + 0,33333...- 0,4 \\ \\ 0,9999... -0,4 \\ \\ 0,59999999... \\ \\ \cong 0,6$

Ou:

$\dfrac{9}{15}$

B)

$(-1,6666... - 0,066666..) \cdot (\frac{15}{8} : 0,25) = \\ \\ -1,73333... \cdot 7,5 \\ \\ \cong -13$

Ou:

$\dfrac{-390}{30}$

C)

$\sqrt[3]{-8} \centerdot \sqrt[]{7^2+15} - (\sqrt[5]{-32} + \sqrt[4]{81} = \\ \\ -2 \centerdot 8 - 1= -17$

D)

Simplificando imediatamente:

$\dfrac{\dfrac{-13}{20} }{\dfrac{30}{99}- \dfrac{1}{2} \centerdot -9-5 \cdot 4-4 } = \dfrac{\dfrac{-13}{20} }{\dfrac{-39}{198 } \centerdot -33 } }} = \dfrac{\dfrac{-13}{20} }{\dfrac{-39}{-6} } = \dfrac{-13}{20} : \dfrac{-39}{-6} = \dfrac{-39: 390 }{60} \\ \\ \\ \Rightarrow \dfrac{-0,1}{60}$

• Att. MatiasHP

Answer 2

Resposta:

Vamos lá!

Explicação passo-a-passo:

• Simplifique as frações, sempre que possível.

Então temos:

$\sqrt{0,444} +0,333-0,4=\\\\\sqrt{\dfrac{4}{9} } +\dfrac{3}{9} -\dfrac{4}{10} =\\\\\\\dfrac{2}{3} +\dfrac{1}{3} -\dfrac{2}{5} =\ mmc=15\\\\\\\dfrac{10+5-6}{15} =\boxed{\dfrac{9}{15} =\boxed{\dfrac{3}{5} }\\}$

$(-1,666-0,0666)\centerdot (\dfrac{15}{8} :0,25)=\\\\\\(-\dfrac{16-1}{9} -\dfrac{6}{90}) \centerdot(\dfrac{15}{8\centerdot0,25}) =\ Simplificando...\\\\\\(-\dfrac{5}{3} -\dfrac{1}{15} )\centerdot(\dfrac{15}{2}) =\ mmc=45\\\\\\-\dfrac{75-3}{45} \centerdot\dfrac{15}{2} =\\\\\\-\dfrac{78}{45} \centerdot(\dfrac{15}{2}) =\\\\\\-\dfrac{26}{15} \centerdot(\dfrac{15}{2}) =\boxed{-\frac{390}{30} =\boxed{-13}}$

$\sqrt[3]{-8} \centerdot \sqrt{7^2 +15} -(\sqrt[5]{-32} +\sqrt[4]{81}= \\\\\ -2\centerdot \sqrt{49 +15} -(-2 +3)} =\\\\-2\centerdot \sqrt{64} -1} =\\\\-2\centerdot8-1=\boxed{-16-1=\boxed{-17}\\}$

$Bons\ estudos!!!\\Prof\ Alexandre$