media aritimetica de 2 terços+1 sexto+1 quarto
Soluções para a tarefa
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1
MA de 2/3, 1/6 e 1/4
MA = 2/3 + 1/6 + 1/4
mmc (2,3,4) = 12
MA = [(12:3.2)/12 + (12:6.1)/12 + (12:4.1)/12] / 3
MA = [8/12 + 2/12 + 3/12] / 3
MA = (13/12)/3
MA = (13/12) .(1/3)
MA = 13/36
MA = 2/3 + 1/6 + 1/4
mmc (2,3,4) = 12
MA = [(12:3.2)/12 + (12:6.1)/12 + (12:4.1)/12] / 3
MA = [8/12 + 2/12 + 3/12] / 3
MA = (13/12)/3
MA = (13/12) .(1/3)
MA = 13/36
gabriel12359:
obrigado mas o mmc e 3,6,4 olhe a pergunta la em cima
Respondido por
1
2/3+1/6+1/4
8+2+3= 13/12
13/12/1/3= 13/36
mmc
3,6,4/2
3,3,2/2
3,3,1/3
1,1,1 mmc= 12
8+2+3= 13/12
13/12/1/3= 13/36
mmc
3,6,4/2
3,3,2/2
3,3,1/3
1,1,1 mmc= 12
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