Question

Me Salllllllllvvvvvaaaaaaaaa
Resolva a equação:

Answer 1

log₈ x . log₄x . log₂x = -4/3

Fazendo a mudança de base para base 2:

(log₂x / log₂8). (log₂x / log₂4). log₂x = -4/3
(log₂x / 3). (log₂x / 2). log₂x = -4/3
(log₂x)³ / 6 = -4/3
(log₂x)³  = -4.6/3
(log₂x)³  = -4.2 = -8
(log₂x)³  = -8
log₂x = $\sqrt[3]{-8}$
log₂x = -2
x = 2⁻²
x = 1/4