Question

Me respondam essa equaçao com base na forma de bhaskara: 3n²-n= 0

Answer 1

3n² - n = 0

a = 3
b = -1
c = 0

Δ = b²−4ac
Δ = (−1)²−4⋅3⋅0
Δ = 1 + 0
Δ = 1


x = -b ± √Δ / 2a
x = -(-1) ± √1 / 2.3
x = 1 ± 1 / 6
x' = 1 - 1 / 6
x' = 0 / 6
x' = 0

x'' = 1 + 1 / 6
x'' = 2 / 6
x'' = 1/3

S = {0, 1/3}