Question

me ajundem!!!!! urgente

Answer 1

a) $\sqrt{36} + \sqrt{4} = 6 + 2 = 8$

b) $\sqrt{64} - 2³ = 8 - 8 = 0$

c) $( \sqrt{81} + 1²) . (3² - \sqrt{49} ) = (9+1) . (9-7) = 10 . 2 = 20$

d) $4 . ( \sqrt{25} + 3) = 4 . (5+3) = 4 . 8 = 32$

e) $[( \sqrt{9}- \sqrt{1} ) . (2³ - \sqrt{25} )] = [(3-1) . (8-5)] = [2.3] = 6$

f) $[(1³ + 2^{4} + 3²) . ( \sqrt{9} - \sqrt{4} )] = [(1+16+9) . (3-2)] = [26 . 1] = 26$

g) ${[(2 + \sqrt{9} . \sqrt{4} ) + ( \sqrt{16} + 2 . 2²)] +3} = {[(2+3 . 2) + (4 + 2 . 4)+3]} =$$= {[(2+6) + (4+8) +3]} = {[8+12+3]} = 23$