Question

Me ajudemmmmmmmmmmmmmmm

Answer 1

Faz o seguinte ... 
$\int (8x - 3)^{7}dx = \\\\ u = 8x -3 \\\\ du =8 dx \to dx = \frac{du}{8} \\\\ \int (u)^{7}\frac{du}{8} = \\\\ \frac{1}{8}\int u^{7}du = \\\\ \frac{1}{8} \frac{u^{7 + 1}}{7+1} + c = \frac{1}{8} \frac{u^{8}}{8}+c = \\\\ \boxed{\frac{1}{64} u^{8} + c}=>\boxed{\boxed{\frac{1}{64} (8x - 3)^{8} + c}}$
Letra (c)