Question

me ajudemmmmm, por favooooor​

Answer 1

Resposta:

${8}^{ {x}^{2} - x} = {4}^{x + 1} \\ ({2}^{ {x}^{2} - x } ) ^{3} = {(2}^{x + 1} ) ^{2} \\ 3 {x}^{2} - 3x = 2x + 2 \\ 3 {x}^{2} - 5x - 2 = 0 \\ x = \frac{5 + - \sqrt{ {( - 5)}^{2} - 4(3)( - 2)} }{2 \times 3} \\ x = \frac{5 + - \sqrt{25 + 24} }{6} \\ x = \frac{5 + - \sqrt{49} }{6} \\ x = \frac{5 + - 7}{6} \\ x = \frac{5 + 7}{6} \\ ou \\ x = \frac{5 - 7}{6} \\ x = 2 \: ou \: x = - \frac{1}{3} \\ \\ se \: x = 2 \\ \\ {8}^{ {x}^{2} - x } = {4}^{x + 1} \\ {8}^{ {2}^{2} - 2} = {4}^{2 + 1} \\ {8}^{2} = {4}^{3} \\ 64 = 64 \\ \\ se \: x = - \frac{1}{3} \\ \\ {8}^{ {x}^{2} - x } = {4}^{x + 1} \\ {8}^{ { - \frac{1}{3} }^{2} - \frac{1}{3} } = {4}^{ - \frac{1}{3} + 1} \\ {8}^{ \frac{1}{9} - \frac{1}{3} } = {4}^{ \frac{2}{3} } \\ {8}^{ - \frac{2}{9} } = {4}^{ \frac{2}{3} } \\( {2}^{ - \frac{2}{9} } ) ^{3} = ( {2}^{ \frac{2}{3} } ) ^{2} \\ {2}^{ - \frac{ 2}{3} } = {2}^{ \frac{4}{3} }$

logo x = 2