Question

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Answer 1

Resposta:

a)

x'=x''=[2+√(4-4)]/2=(2+0)/2=1

b)

x'=[-1+√(1+24)]/2=(-1+5)/2=2

x''=[-1-√(1+24)]/2=(-1-5)/2=-3

c)

x'=[1+√(1+24)]/2=(1+5)/2=3

x''=[1-√(1+24)]/2=(1-5)/2=-2

d)

x'=[-5+√(25-24)]/2=(-5+1)/2 =-2

x''=[-5-√(25-24)]/2=(-5-1)/2 =-3

e)

x'=[5+√(25-24)]/2=(5+1)/2 =3

x''=[5-√(25-24)]/2=(5-1)/2 =2

f)

x'=[-1+√(1+4)]/2=[-1+√5]/2

x''=[-1-√(1+4)]/2=[-1-√5]/2

g)

x'=[-1+√(1+80)]/2=(-1+9)/2=4

x''=[-1-√(1+80)]/2=(-1-9)/2=-5

h)

x'=[3+√(9+16)]/2=(3+5)/2=4

x''=[3-√(9+16)]/2=(3-5)/2=-1

i)

Cuidado aqui ==>x²+-8x+7=0   , coloquei x²-8x+7=0

x'=[8+√(64-28)]/2=(8+6)/2=7

x''=[8-√(64-28)]/2=(8-6)/2=1

j)

x'=[2+√(4+32)]/2=(2+6)/2=4

x''=[2-√(4+32)]/2=(2-6)/2=-2