Question

ME AJUDEMMMM POR FAVOR

Answer 1

Resposta:

Explicação passo-a-passo:

 $tg60=\frac{co}{ca} \\\\\sqrt{3} =\frac{y}{\sqrt{3} } \\\\y=\sqrt{3} .\sqrt{3} \\\\y=\sqrt{9} \\\\y=3$

$cos30=\frac{ca}{h} \\\\\frac{\sqrt{3} }{2} =\frac{9}{y} \\\\\sqrt{3} .y=18\\\\y=\frac{18}{\sqrt{3} } \\\\y=\frac{18,\sqrt{3} }{\sqrt{3}\sqrt{3} } \\\\y=\frac{18\sqrt{3} }{3} \\\\y=6.\sqrt{3}$