Question

me ajudemmm pfvr nessas expressões ​

Answer 1

Resposta:

.,.........................

Answer 2

Resposta: b) 9

Explicação passo-a-passo:

Usando as propriedades:

$\frac{x^a}{x^b} =x^{a-b}\\x^a*x^b=x^{a+b}\\(x^a)^b=x^{a*b}$

$(\frac{3^8}{(3^2)^2} )^\frac{1}{2} = (\frac{3^8}{3^4})^\frac{1}{2} = \frac{3^8^*^1^/^2}{3^4^*^1^/^2} = \frac{3^8^/^2}{3^4^/^2} =\frac{3^4}{3^2} =3^{4-2}=3^2=9$