Question

Me ajudemmm! é pra hj!!

Answer 1

1) a) $\sqrt{49} + \sqrt{81} = \sqrt{ 7^{2} } + \sqrt{ 3^{4} } = 7+9 = 16$

$\sqrt[3]{64} - \sqrt[3]{-1} = \sqrt[3]{ 2^{6} } - \sqrt[3]{(-1)} = 2^{2} -(-1) = 4+1 = 5$

$\sqrt{4} - \sqrt[3]{27} + \sqrt[4]{16} - \sqrt[5]{-1} = \sqrt{ 2^{2} } - \sqrt[3]{ 3^{3} } + \sqrt[4]{ 2^{4} } -(-1) \\ \\ 2-3+2+1 = 2$

$3 \sqrt{25} +2 \sqrt{4} -5 \sqrt[3]{8} = 3 \sqrt{ 5^{2} } +2 \sqrt{ 2^{2} } -5 \sqrt[3]{ 2^{3} } = 3.5+2.2-5.2 \\ \\ 15+4-10 = 9$